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Two 0.50-kg carts are pushed toward each other from starting positions at either end of a 6.0-m low-friction track. Each cart is pushed with a force of 3.0 N, and that force is exerted for a distance of 1.0 m. (a) What is the work done on the two-cart system? (b) What is the change in kinetic energy of the system? (c) What is the kinetic energy of the center of mass of the system?

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Answered 2 years ago
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Given data:

mass of the carts mm = 0.50 kg0.50\ \text{kg}

distance between the carts xx = 6.0 m6.0\ \text{m}

force exerted FF = 3.0 N3.0\ \text{N}

distance of push dd = 1.0 m1.0\ \text{m}

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