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Two blocks are in contact on a frictionless table. A horizontal force is applied to one block, as shown in earlier Fig. (a)(a) If m1=2.3m_1=2.3 kg, m2=1.2m_2=1.2 kg, and F=3.2F=3.2 N, find the force of contact between the two blocks. (b)(b) Show that if the same force FF is applied to m2m_2 rather than to m1m_1 , the force of contact between the blocks is 2.12.1 N, which is not the same value de- rived in (a)(a). Explain.

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Introduction\textbf{Introduction}

The two blocks have a common acceleration of

a=F(m1+m2)\begin{align*} a = \frac{F}{(m_1+m_2)}\end{align*}

where FF is the force applied to the first block, m1m_1 is the mass of block 1, and m2m_2 is the mass of block 2.

As force was applied to block 1, a force was also felt by block 2 due to block 1. This force between block 1 and block 2 is the force of contact, denoted as PP.

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