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Two diploid species of closely related frogs, which we will call species A and species B, were analyzed with regard to genes that encode an enzyme called hexokinase. Species A has two distinct copies of this gene: and . In other words, this diploid species is A1A1 A2A2. The other species has three copies of the hexokinase gene, which we will call , and . A diploid individual of species would be . These hexokinase genes from the two species were subjected to DNA sequencing, and the percentage of sequence identity was compared among these genes. The results are shown here:
If we assume that hexokinase genes were never lost in the evolution of these frog species, how many distinct hexokinase genes do you think there were in the most recent ancestor that preceded the divergence of these two species? Explain your answer. Also explain why species has three distinct copies of this gene, whereas species A has only two.
Solution
VerifiedOn comparing the percentages of similarity between the genes we can see that the A1 gene has the maximum similarity (94%) with the B2 gene. On the other hand. A2 gene has maximum similarity (91% and 92%) with both B1 and B3 genes respectively. Thus before the evolution of hexokinase gene in the A and B species, into A1. A2 and B1. B2 and B3. there were only two copies of the gene before the formation of the two species.
This can be explained by saying that neutral mutations would have resulted in the formation of different copies of the gene that encodes for hexokinase enzyme. Thus though the gene is not lost in the evolution of these frogs, still there exists a genetic variation in the copies of the genes. Once the two species of frogs. A and B. were formed, then it seems likely that one of the B genes would have undergone duplication yet again, to form the B3 gene. It seems more likely that the B3 gene would have formed from the B1 gene as the percentage of similarity between the two is high. Thus species B has three distinct copies.
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