## Related questions with answers

Two examples analyzed whether telephone callers to an airline would stay on hold different lengths of time, on average, if they heard

(a) an advertisement about the airline,

(b) Muzak, or

(c) classical music. The sample means were 5.4, 2.8, and 10.4, with $n_1$ = $n_2$ = $n_3$ = 5. The ANOVA test had F = 74.6/11.6 = 6.4 and a P-value of 0.013.

The 95% confidence intervals are (0.3, 9.7) for $\mu_3$ - $\mu_1$ and (-2 .1, 7.3) for $\mu_1$ - $\mu2$. Interpret these two confidence intervals. Using these two intervals and the interval from part a, summarize what the airline company learn ed from this study.

Solution

VerifiedGiven:

- 95% confidence interval for $\mu_3-\mu_2$: $(2.9,12.3)$
- 95% confidence interval for $\mu_3-\mu_1$: $(0.3,9.7)$
- 95% confidence interval for $\mu_1-\mu_2$: $(-2.1,7.3)$

We need to interpret the confidence intervals for $\mu_3-\mu_1$ and for $\mu_1-\mu_2$, and summarize the overall results.

We are 95% confident that the population parameter lies within the confidence interval.

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