## Related questions with answers

Question

Two examples analyzed whether telephone callers to an airline would stay on hold different lengths of time, on average, if they heard

(a) an advertisement about the airline,

(b) Muzak, or

(c) classical music. The sample means were 5.4, 2.8, and 10.4, with $n_1$ = $n_2$ = $n_3$ = 5. The ANOVA test had F = 74.6/11.6 = 6.4 and a P-value of 0.013.

A 95% confidence interval comparing the population mean times that callers are willing to remain on hold for classical music and Muzak is (2.9, 12.3). Interpret this interval.

Solution

VerifiedAnswered 1 year ago

Answered 1 year ago

Step 1

1 of 3Given 95% confidence interval of the population mean difference between classical music and Muzak:

$(2.9,12.3)$

We need to interpret the confidence interval.

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