Related questions with answers
Two long parallel plates are separated by a distance of 15.0 cm. The bottom plate is kept at a potential of −250 V and the top at
. A charge of
is placed at a point 3.00 cm from the bottom plate. a. Find the electric potential energy of the charge. The charge is then moved vertically up to a point 3.00 cm from the top plate. b. What is the electrical potential energy of the charge now? c. How much work was done on the charge?
Solution
VerifiedThe potential at a distance from the bottom plate can be written as follows
Where is the electric potential of the bottom plate and is the electric field between the two plates, and we know that the electric field between the two plates is , where cm). Thus, the electric potential at a distance from the bottom plate is
now that we have the potential at the position of the charge, we can calculate its electric potential energy as follows
The charge is now at a distance of (12 cm) from the bottom plate, so the potential at this point can be determined as follows
and the electric potential energy is therefore
The work equals the change in the potential energy
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