Question

# Two narrow slits are 0.12 mm apart. Light of wavelength 550 nm illuminates the slits, causing an interference pattern on a screen 1.0 m away. Light from each slit travels to the m = 1 maximum on the right side of the central maximum. How much farther did the light from the left slit travel than the light from the right slit?

Solution

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If we denote the angle at which the $m=1$ fringe is found as $\theta_1$, we can write the difference in the paths taken by the light $\delta$ as

\begin{align*} \delta=d\sin\theta_1 \tag{1} \end{align*}

where $d$ is the distance between the slits.

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