## Related questions with answers

Two pipes A and B can fill a tank in 24 minutes and 32 minutes, respectively. Initially, both pipes are opened simultaneously. After how many minutes should pipe B be turned off so that the tank is full in 18 minutes?

Solution

VerifiedPipe A run for 18 minutes. Because pipe A can fill a whole tank in 24 minutes, if pipe A work 18 minutes she can fill

$\dfrac{18\text{ minutes}}{24 \text{minuites per tank}}=\dfrac{3}{4}\text{ tank}$

So, for 18 minutes pipe A can fill $\dfrac{3}{4}$ of a tank.

$\dfrac{1}{4}$ tank will need to fill pipe B.

Because pipe B can fill a whole tank in 32 minutes, to fill $\dfrac{1}{4}$ tank she needs one-fourth of 32 minutes because pipe need to fill $\dfrac{1}{4}$ tank, not a whole tank.

$\dfrac{32}{4}=8\text{ minutes}$

To fill a tank for 18 minutes if pipe A work all the time(18 minutes), after 8 minutes pipe B should be turned off.

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