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Question

Two planes are given parametrically by the vector equations

x1(s,t)=(3,4,9)+s(9,5,9)+t(3,2,3)x_1(s, t) = (−3, 4,−9) + s(9,−5, 9) + t(3,−2, 3)

x2(s,t)=(5,0,3)+s(9,2,9)+t(4,7,4).x_2(s, t) = (5, 0, 3) + s(−9, 2,−9) + t(−4, 7,−4).

(a) Give a convincing explanation for why these planes are parallel. (b) Find the distance between the planes.

Solution

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(a)\mathbf{(a)} Notice that

(9,5,9)×(3,2,3)=(3,0,3)(9,-5,9)\times (3,-2,3) = (3,0,-3)

and

(9,2,9)×(4,7,4)=(55,0,55)=355(3,0,3)(-9,2,-9)\times(-4,7,-4) = (55,0,-55) = \frac{3}{55}(3,0,-3)

So both planes are perpendicular to (3,0,3)(3,0,-3). So they are parallel.

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