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Two point charges are placed on the x-axis as follows: Charge is located at x = 0.200 m, and charge is at x = -0.300m. What are the magnitude and direction of the total force exerted by these two charges on a negative point charge that is placed at the origin?
Solutions
VerifiedTo find the force on , we need to calculate the magnitudes and direction of the force for each interaction, and then sum them accordingly.
We will calculate all the forces according to Coulomb's law, which describes the force between two charges and on distance :
is the electric permitivity of vacuum. We will use an approximate value of the whole constant factor:
The net force on charge we will get using the concept of superposition, which allows us to calculate the net force by simply summing the force of each charge interacting with charge Q.
The magnitude F of the force that each of two point charges q1 and q2 a distance r apart exerts on each other is directly proportional to the product of the charges (q1*q2) and inversely proportional to the square of the distance between them. This relationship is called Coulomb�s law.
The forces that two charges exert on each other always act along the line joining the charges. The two forces are always equal in magnitude and opposite in direction, even when the charges are not equal. The forces obey Newton�s third law.
Apply: in most problems we are asked to get the force directly using the other variables (the magnitude of charges and the distance between them). But, in other problem we have to solve the equation for another variable such as the distance and use the given variables ti get the required variable.
The force on due to is towards the positive x-axis while due to is directed towards the negative x-axis. This is because both and attract towards itself. Hence the force on due to and are in opposite directions.
The net force acting on is given by
Substituting the values of , and we get,
N, in the positive x-direction.
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