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Unless indicated otherwise, assume the speed of sound in air to be v = 344 m/s. A loud factory machine produces sound having a displacement amplitude of 1.00μm1.00 \mu \mathrm{m}, but the frequency of this sound can be adjusted. In order to prevent ear damage to the workers, the maximum pressure amplitude of the sound waves is limited to 10.0 Pa. Under the conditions of this factory, the bulk modulus of air is 1.42×105Pa1.42 \times 10^{5} \mathrm{Pa}. What is the highest frequency sound to which this machine can be adjusted without exceeding the prescribed limit? Is this frequency audible to the workers?

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The relation that describes the pressure amplitude for a sound wave is

Pmax=BkA\begin{align} P_{\text{max}}=BkA \end{align}

Where the bulk modulus of the air is B=1.42×105B=1.42 \times 10^{5} Pa and the displacement amplitude of the waves produced by the machine is 1 μm1 \mathrm{~ \mu m}.

Using (1) we can calculate kk then we can use kk to determine the wavelength λ\lambda of the wave, and remember that λ=2π/k\lambda=2\pi/k.

So, substitute into (1) with 10 Pa for PmaxP_{\text{max}}, (1.42×105(1.42 \times 10^{5} Pa) for BB and 1×106 m1\times 10^{-6} \mathrm{~ m} for AA

10 Pa=(1.42×105 Pa)×k×(1×106 m)10 \mathrm{~ Pa}=( 1.42 \times 10^{5} \mathrm{~ Pa} ) \times k\times (1\times 10^{-6} \mathrm{~ m})

k=10 Pa(1.42×105 Pa)×(1×106 m)k=\frac{10 \mathrm{~ Pa}}{( 1.42 \times 10^{5} \mathrm{~ Pa} ) \times (1\times 10^{-6} \mathrm{~ m})}

k=70.4 m1k=70.4 \mathrm{~ m^{-1}}

We can use the following relation to calculate the wavelength

λ=2πk=2π70.4 m1\lambda=\frac{2 \pi}{k}=\frac{2 \pi}{70.4 \mathrm{~ m^{-1}}}

λ=0.089 m\lambda=0.089 \mathrm{~ m}

Finally, the relation between the wavelength and the frequency of a sound wave is given by the following equation

f=vλ\begin{align} f=\frac{v}{\lambda} \end{align}

f=344 m/s0.089 mf=\frac{344 \mathrm{~ m/s}}{0.089 \mathrm{~ m}}

f=3.86×103 Hz\boxed{f=3.86 \times 10^{3}\mathrm{~ Hz}}

Since ff is in the range of [20 Hz - 20,000 Hz] which is the range of audible frequencies, the frequency is audible.

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