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Question

# Use a computer algebra system to find the second derivative of the function. \$g(\theta)=\tan 3 \theta-\sin (\theta-1)$

Solution

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Given:

\begin{aligned} g(\theta)=\tan{3\theta}-\sin{(\theta-1)} \end{aligned}

Using a computer algebra system, we found that:

\begin{aligned} g'(\theta)&=3\sec^2\left(3{\theta}\right)-\cos\left({\theta}-1\right)\\ g''(\theta)&=18\sec^2\left(3{\theta}\right)\tan\left(3{\theta}\right)+\sin\left({\theta}-1\right) \end{aligned}

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