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Question

Use integration to compute the volume of a right circular cone generated by revolving the ordinate set of a linear function f(x)=cx over the interval 0xb0 \leq x \leq b. Show that the result is one-third the area of the base times the altitude of the cone.

Solution

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For the purpose of making it clear to you, a graph is attached below. We can see that we are rising in the yy direction rr units and moving in the xx-axis hh units, so the equation of our lines would be given by y=rhxy=\dfrac{r}{h} x. In our problem, h=bh=b and c=rh=rbc=\dfrac{r}{h}=\dfrac{r}{b}.

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