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# Use long division to divide.$(x^3+4x^2-3x-12)\div(x-3)$

Solution

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We use long division to divide the expressions.

$\begin{array}{l} \phantom{x+2;}{~~~~~~~~~~~~~x^2+7x+18}\\ x-3\overline{\smash{)}~~~x^3+4x^2-3x-12}\\ \phantom{x-3;}\underline{-x^3+3x^2}\\ \phantom{{x-3;}4x}~~~~~~~~7x^2-3x\\ \phantom{{x-3;}4~^3+}\underline{-7x^2+21x}\\ \phantom{{x-3+;}4x^3~~~~~~~~~~+}{18x-12}\\ \phantom{{x-3;}4x^3~~~~~~~~~~+}\underline{-18x+54}\\ \phantom{{x-3+;}4x^3~~~~~~~~~~~~~~~~~~~~~+}{42}\\ \end{array}$

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