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Question

Use the axioms of a vector space to prove that

(a+b)(u+v)=au+av+bu+bv(a+b)(u+v)=au+av+bu+bv

for all scalars aa and bb and all vectors uu and vv in a vector space.

Solution

Verified

Let u\bold{u} and v\bold{v} be a vector in VV and aa and bb scalars. By axiom 8:

(a+b)(u+v)=a(u+v)+b(u+v)(a+b)(\bold{u}+\bold{v})=a(\bold{u}+\bold{v})+b(\bold{u}+\bold{v})

By axiom 7:

(a+b)(u+v)=au+av+bu+bv(a+b)(\bold{u}+\bold{v})=a\bold{u}+a\bold{v}+b\bold{u}+b\bold{v}

\square

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