## Related questions with answers

Question

Use the $\epsilon=\delta$ definition of limit to verify the limit statements given.

$\lim _{(x, y) \rightarrow(0,0)}\left(x+y^{2}\right)=0$

Solution

VerifiedAnswered 1 year ago

Answered 1 year ago

Step 1

1 of 4Using $\epsilon$-$\delta$ definition of the limit we prove that $(x+y^{2})\to 0$ as ${(x, y)\rightarrow(0, 0)}$.

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