## Related questions with answers

Question

Use the Law of Cosines to solve the triangle. $B=48^{\circ}, \quad a=18, \quad c=12$

Solutions

VerifiedSolution A

Solution B

Answered 1 year ago

Step 1

1 of 4To solve the triangle, use the Law of cosine and the property of sum of interior angles of triangle given by:

$b^2=a^2+c^2-2ac\cos B$

$A+B+C=180^{\circ}$

Perform series of operation applicable and simplify.

Answered 2 years ago

Step 1

1 of 4By using the standard form of the Law of Cosines

$\begin{aligned} b^2&=a^2+c^2-2ac\cos B\\[10pt] &=18^2+12^2-2(18)(12)\cos48^{\circ}\\[10pt] &\approx178.94 \end{aligned}$

from which

$\boxed{b\approx13.38}$

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