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Use the laws of conservation of energy, charge, and nucleon number to decide which of the following processes are impossible. Give your reasons. (a) 207Po207At+e+νˉ{ }^{207} \mathrm{Po} \rightarrow{ }^{207} \mathrm{At}+\mathrm{e}^{-}+\bar{\nu} (b) 213Rn208Po+α{ }^{213} \mathrm{Rn} \rightarrow{ }^{208} \mathrm{Po}+\alpha (c) 212Po208 Pb+α{ }^{212} \mathrm{Po} \rightarrow{ }^{208} \mathrm{~Pb}+\alpha (d) p+14 Nα+12C\mathrm{p}+{ }^{14} \mathrm{~N} \rightarrow \alpha+{ }^{12} \mathrm{C} (e) n+22Nap+22Ne\mathrm{n}+{ }^{22} \mathrm{Na} \rightarrow \mathrm{p}+{ }^{22} \mathrm{Ne}

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Conservation of energy says that the initial energy of a system does not change through time.

KEi+Mic2=KEf+Mfc2KE_i+M_ic^2=KE_f+M_fc^2

Rearranging this, we have

KEfKEi=(MiMf)c2KE_f-KE_i=(M_i-M_f)c^2

The quantity KEfKEiKE_f-KE_i can only be positive, therefore the condition Mi>MfM_i>M_f should be followed in order for a reaction to be possible.

Conservation of nucleon number says that the number of protons and neutrons stays the same in a nuclear reaction.

Ainitial=Afinal\sum A_\text{initial}=\sum A_\text{final}

Conservation of total charge says that the total charge also does not change.

qinitial=qfinal\sum q_\text{initial}=\sum q_\text{final}

If protons are the only charged particles involved, conservation of charge implies that the proton number should not change.

Zinitial=Zfinal\sum Z_\text{initial}=\sum Z_\text{final}

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