## Related questions with answers

Question

**Use the left-to-right elimination method to solve the systems.**

$\left\{\begin{array}{r}x-3 y-z=0 \\ x-2 y+z=8 \\ 2 x-6 y+z=6\end{array}\right.$

Solution

VerifiedAnswered 2 years ago

Answered 2 years ago

Step 1

1 of 6We have,

$~x-3y-z=0\tag{1}$

$~x-2y+z=8\tag{2}$

$2x-6y+z=6\tag{3}$

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