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Question

Use the utility to graph the function and its tangent line in the same viewing window. \

y=(t29)t+2,(2,10)y=\left(t^2-9\right) \sqrt{t+2}, \quad(2,-10)

Solution

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Answered 1 year ago
Answered 1 year ago

Enter the given function in Y1 and the tangent line equation that we found in part (b),

y=274t472y=\dfrac{27}{4}t-\dfrac{47}{2}

in Y2 (change tt to X) as shown:

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