Question

Using the Maclaurin series, show that if f(z) is even, its integral (with a suitable constant of integration) is odd.

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Assume we are given arbitrary function f(x)f(x). Maclaurin series of this function is Taylor series at the point z0=0z_0=0. In other words, Maclaurin series is the following series:

f(z)=n=0anzn\begin{equation*} f(z)=\sum_{n=0}^{\infty}a_nz^n \end{equation*}

where coefficients ana_n are calculated with following formula:

an=1n!f(n)(0)a_n=\frac{1}{n!}\cdot f^{(n)}(0)

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