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Question

Using what you have learned about transformations of the graph y=1xy=\frac{1}{x}, can you find the equations of the asymptotes of the function f(x)=pcx+d+qf(x)=\frac{p}{c x+d}+q, and hence state the domain and range?

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Answered 2 years ago
Answered 2 years ago

Since the asymptotes of the graph of the function y=1xy=\dfrac{1}{x} are x=0x=0 and y=0y=0, and in order to obtain the graph of the function y=pcx+d+qy=\dfrac{p}{cx+d}+q, we use the horizontal translation by cd\dfrac{c}{d} units therefore the vertical asymptote will also translate horizontally and it will be x=dcx=-\dfrac{d}{c}. The graph also vertically translate qq units which leads the horizontal asymptote to translate qq units vertical and the equation will be y=qy=q.

  • Vertical asymptote is x=dcx=-\dfrac{d}{c} implies the domain is R{dc}\mathbb{R}-\left\{-\dfrac{d}{c}\right\}.
  • Horizontal asymptote is y=qy=q implies the range is R{q}\mathbb{R}-\{q\}.

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