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Question

Verify each identity. Give the domain of validity for each identity. sinθtanθ=1cosθcosθ\sin \theta \tan \theta=\frac{1}{\cos \theta}-\cos \theta

Solution

Verified

Given: sinθtanθ=1cosθcosθ\sin\theta\tan\theta=\dfrac{1}{\cos\theta}-\cos\theta

We work using the left side. Apply the tangent identity:

sinθtanθ=sinθsinθcosθ\sin\theta\tan\theta=\sin\theta\cdot\frac{\sin\theta}{\cos\theta}

sinθtanθ=sin2θcosθ\sin\theta\tan\theta=\frac{\sin^2\theta}{\cos\theta}

Apply the Pythagorean identity (cos2θ+sin2θ=1)(\cos^2\theta+\sin^2\theta=1):

sinθtanθ=1cos2θcosθ\sin\theta\tan\theta=\frac{1-\cos^2\theta}{\cos\theta}

sinθtanθ=1cosθcos2θcosθ\sin\theta\tan\theta=\frac{1}{\cos\theta}-\frac{\cos^2\theta}{\cos\theta}

sinθtanθ=1cosθcosθ\color{#c34632}{ \sin\theta\tan\theta=\frac{1}{\cos\theta}-\cos\theta}

The domains of sinθ\sin\theta and cosθ\cos\theta is all real numbers. The domains of tanθ\tan\theta and 1cosθ\dfrac{1}{\cos\theta } exclude all zeros of cosθ\cos\theta which are the odd multiples of π2\dfrac{\pi}{2}.

Domain of validity:\textbf{\color{#c34632}{Domain of validity:}} All real numbers except for odd multiples of π2\dfrac{\pi}{2}.

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