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Question

Verify that each trigonometric equation is an identity. sin2β(1+cot2β)=1\sin ^{2} \beta\left(1+\cot ^{2} \beta\right)=1

Solution

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Step 1
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Work on the more complex side, which is the left side.

Use the Pythagorean identity: 1+cot2β=csc2β1+\cot^2\beta=\csc^2\beta

sin2β(1+cot2β)=sin2β(csc2β)\sin^{2}\beta\left(1+\cot^{2}\beta\right)=\sin^{2}\beta\left(\csc^{2}\beta\right)

Use the reciprocal identity: cscβ=1sinβ\csc\beta=\dfrac{1}{\sin\beta}

sin2β(1+cot2β)=sin2β1csc2β\sin^{2}\beta\left(1+\cot^{2}\beta\right)=\sin^{2}\beta\cdot\dfrac{1}{\csc^{2}\beta}

sin2β(1+cot2β)=1(1)\color{#c34632}\sin^{2}\beta\left(1+\cot^{2}\beta\right)=1\hspace{2mm}\checkmark\color{white}\tag{1}

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