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Question

View at least two cycles of the graphs of the given functions on a calculator. y=2cot(2x+π6)y=-2 \cot \left(2 x+\frac{\pi}{6}\right)

Solution

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We are given:

y=2cot(2x+π6)y=-2\cot \left(2x+\dfrac{\pi}{6}\right)

The function y=acot(bx+c)y=a\cot (bx+c) has a period of πb\dfrac{\pi}{b}. Two asymptotes can be located at x=0x=0 and x=πbx= \dfrac{\pi}{b}. The displacement is cb-\dfrac{c}{b}. The range is all real numbers.

From the given, b=2b=2 and c=π6c=\frac{\pi}{6} so the period is π2\frac{\pi}{2} and there is an asymptote at x=0x=0. The displacement π/62=π12-\frac{\pi/6}{2}=-\frac{\pi}{12}. So, we use the following window setting:

  • Xmin = 0.3-0.3 (The asymptote is shifted by the displacement at x=0π120.26x=0-\frac{\pi}{12}\approx -0.26)
  • Xmax = 3.53.5 (For two periods, the curve ends at x=0+2(π/2)=π3.1x=0+2(\pi/2)=\pi\approx 3.1)
  • Ymin = 10-10, Ymax = 1010 (this shows enough of the curve)

(1)\color{white}\tag{1}

Graph y1=2(tan(2x+π/6))1y_1=-2(\tan (2x+\pi/6))^{-1}. Using a graphing calculator in RADIAN mode, the graph will be:

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