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Water towers store water above the level of consumers for times of heavy use, eliminating the need for high-speed pumps. How high above a user must the water level be to create a gauge pressure of 3.00×105 N/m23.00 \times 10^5 \mathrm{~N} / \mathrm{m}^2 ?

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P=3105Nm2ρw=1000kgm3\begin{align*} P&=3\cdot 10^{5}\, \dfrac{\text{N}}{\text{m}^2} \\ \rho_w&=1000\, \dfrac{\text{kg}}{\text{m}^3} \end{align*}

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