We frequently must solve equations of the form f(x) = 0. When f is a continuous function on [a, b] and f(a) and f(b) have opposite signs, the intermediate-value theorem guarantees that there exists at least one solution of the equation f(x) = 0 in [a, b]. (a) Explain in words why there exists exactly one solution in (a, b) if, in addition, f is differentiable in (a, b) and is either strictly positive or strictly negative throughout (a, b). (b) Use the result in (a) to show that has exactly one solution in [−1, 1].
Solution
Verified(a)
If is an increasing function on is one to one mapping, that means, any -value has exactly one -value such that . Here, for , there is exactly one such that . The same conclusion is obtained if (except, is than decreasing).
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