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Question

What is the formula for the surface area of a right circular cylinder, S=2πrh+2πr2,S=2 \pi r h+2 \pi r^{2}, solved for h? A.h=S4πr B.h=s2πr2 C.h=S2πrr D.h=rS2πrA. h=\frac{S}{4 \pi r}\ B. h=\frac{s}{2 \pi r^{2}}\ C. h=\frac{S}{2 \pi r}-r\ D. h=r-\frac{S}{2 \pi r}

Solution

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S(2×(π)r2)=2×(π)rhS-(2\times(\pi)r^{2})=2\times(\pi)rh

From the given equation, subtract (2×(π)r2)(2\times(\pi)r^{2}) from both sides in order to isolate h.

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