Question

What is the mass percent of nitrogen in ammonium carbonate, (NHX4)X2COX3\ce{(NH4)2CO3}?

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Answered 9 months ago
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To determine the mass percentage of nitrogen, first we have to calculate the molar mass of ammonium carbonate ((NHX4)X2COX3)\ce{((NH4)2CO3)}.

The molar mass of N\ce{N} is 14.007g/mol\ce{14.007 g/mol}

The molar mass of H\ce{H} is 1.008g/mol\ce{1.008 g/mol}

The molar mass of C\ce{C} is 12.011g/mol\ce{12.011 g/mol}

The molar mass of O\ce{O} is 16.000g/mol\ce{16.000 g/mol}

Therefore, the molar mass of ammonium carbonate is

M((NHX4)X2COX3)=(M(N)+M(H) ×4) ×2+M(C)+M(O) ×3=(14.007+1.008×4) ×2+12.011+16.000×3=96.089g/mol\begin{align*} \ce{M((NH4)2CO3)} &= \ce{ (M(N) + M(H) \times 4) \times 2 + M(C) + M(O) \times 3 }\\ &= \ce{ (14.007 + 1.008 \times 4) \times 2 + 12.011 + 16.000 \times 3 }\\ &= \ce{96.089 g/mol} \end{align*}

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