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Question

What volume of a 2.0 M solution is needed to provide 0.50 mol of NaOH? (1) 0.25 L (2) 0.50 L (3) 1.0 L (4) 2.0 L

Solution

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To calculate this problem we can use equation:

C=nV\text{C}=\dfrac{\text{n}}{\text{V}}

C is molarity

n is number of moles of solute

V is the volume of solution

From above equation we see that:

V=nCV=0.52=0.25L\begin{align*} \mathrm{V}&=\dfrac{\mathrm{n}}{\mathrm{C}} \\ \mathrm{V}&=\dfrac{0.5}{2}=0.25 \mathrm{L} \end{align*}

Answer is (1)\textbf{(1)}.

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