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Question

When 20.0 g20.0 \mathrm{~g} of mercury are heated from 10.0C10.0^{\circ} \mathrm{C} to 20.0C20.0^{\circ} \mathrm{C}, 27.6 J27.6 \mathrm{~J} of energy are absorbed. What is the specific heat of mercury?

(a) 0.726 J/gC0.726 \mathrm{~J}/\mathrm{g}^{\circ} \mathrm{C}
(b) 0.138 J/gC0.138 \mathrm{~J}/\mathrm{g}^{\circ} \mathrm{C}
(c) 2.76 J/gC2.76 \mathrm{~J}/\mathrm{g}^{\circ} \mathrm{C}
(d) no correct answer given

Solution

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Answered 1 year ago
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In this problem, we are asked to determine the specific heat of mercury. To answer this, we will use the formula:

specific heat=heatmass×Δt\begin{aligned} \text{specific heat}= \dfrac{\text{heat}}{\text{mass} \times \Delta t} \end{aligned}

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