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Question

When $20.0 \mathrm{~g}$ of mercury are heated from $10.0^{\circ} \mathrm{C}$ to $20.0^{\circ} \mathrm{C}$, $27.6 \mathrm{~J}$ of energy are absorbed. What is the specific heat of mercury?

(a) $0.726 \mathrm{~J}/\mathrm{g}^{\circ} \mathrm{C}$

(b) $0.138 \mathrm{~J}/\mathrm{g}^{\circ} \mathrm{C}$

(c) $2.76 \mathrm{~J}/\mathrm{g}^{\circ} \mathrm{C}$

(d) no correct answer given

Solution

VerifiedAnswered 1 year ago

Answered 1 year ago

Step 1

1 of 5In this problem, we are asked to determine the specific heat of mercury. To answer this, we will use the formula:

$\begin{aligned} \text{specific heat}= \dfrac{\text{heat}}{\text{mass} \times \Delta t} \end{aligned}$

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