## Related questions with answers

When air is inhaled, it enters the alveoli of the lungs, and varying amounts of the component gases exchange with dissolved gases in the blood. The resulting alveolar gas mixture is quite different from the atmospheric mixture. The following table presents selected data on the composition and partial pressure of four gases in the atmosphere and in the alveoli:

$\begin{array}{|c|c|c|c|c|} \hline \text { Gas } & \text { Mole \% } & \begin{array}{l} \text { Partial } \\ \text { Pressure (torr) } \end{array} & \text { Mole \% } & \begin{array}{l} \text { Partial } \\ \text { Pressure (torr) } \end{array} \\ \hline \mathrm{N}_2 & 78.6 & - & - & 569 \\ \hline \mathrm{O}_2 & 20.9 & - & - & 104 \\ \hline \mathrm{CO}_2 & 00.04 & - & - & 40 \\ \hline \mathrm{H}_2 \mathrm{O} & 00.46 & - & - & 47 \\ \hline \end{array}$

If the total pressure of each gas mixture is $1.00 \mathrm{~atm}$, calculate:

(a) The partial pressure (in torr) of each gas in the atmosphere

(b) The mole % of each gas in the alveoli

(c) The number of $\mathrm{O}_2$ molecules in $0.50 \mathrm{~L}$ of alveolar air (volume of an average breath of a person at rest) at $37^{\circ} \mathrm{C}$

Solutions

VerifiedIn this exercise, we must determine the partial pressure of each gas in the atmosphere knowing their mole percents.

$\textbf{a)}$

Total pressure:1 atm=760 torr

Partial pressure=total pressure*mole percentage

Partial pressure(N$_{2}$)=760torr*0,786=597,36torr

Partial pressure(O$_{2}$)=760torr*0,209=158,84torr

Partial pressure(CO$_{2}$)=760torr*0,0004=0,304torr

Partial pressure(H$_{2}$O)=760torr*0,0046=3,496torr

## Create an account to view solutions

## Create an account to view solutions

## Recommended textbook solutions

#### Chemistry: The Molecular Nature of Matter and Change

7th Edition•ISBN: 9780073511177 (2 more)Patricia Amateis, Silberberg#### Chemistry

10th Edition•ISBN: 9781305957404 (1 more)Donald J. DeCoste, Steven S. Zumdahl, Susan A. Zumdahl#### Chemistry, AP Edition

10th Edition•ISBN: 9781305957732 (1 more)Donald J. DeCoste, Steven S. Zumdahl, Susan A. Zumdahl## More related questions

1/4

1/7