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Question
When light of wavelength 350 nm falls on a potassium surface, electrons having a maximum kinetic energy of 1.31 eV are emitted. Find the frequency corresponding to the cutoff wavelength.
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Answered 2 years ago
Step 1
1 of 5In this problem, light of wavelength is incident on a potassium surface. The electrons ejected have a maximum kinetic energy of . For this part, we calculate the cut-off frequency of the potassium's wave function.
Answered 2 years ago
Step 1
1 of 4Given values:
,
In part we have to find the frequency corresponding to the cutoff wavelength.
Answered 2 years ago
Step 1
1 of 2Hence, from the solution where cutoff wavelength is . For the wavelength corresponding frequency, it follows:
Therefore, substituting initial values, we get:
Solution is:
Answered 2 years ago
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