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# When light of wavelength 350 nm falls on a potassium surface, electrons having a maximum kinetic energy of 1.31 eV are emitted. Find the frequency corresponding to the cutoff wavelength.

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In this problem, light of wavelength $\lambda = 350~\mathrm{nm}$ is incident on a potassium surface. The electrons ejected have a maximum kinetic energy of $KE_\text{max} = 1.31~\mathrm{eV}$. For this part, we calculate the cut-off frequency of the potassium's wave function.

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