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Question

When the string is pulled with a force pp tangent to the rim, it gives the cylinder an angular acceleration α\alpha, if the cylinder had fourfold the radius but everything else was the same the angular acceleration would be?

Solution

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Answered 7 months ago
Answered 7 months ago
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Explanation:

As we know, the angular acceleration of the cylinder is equal:

α=τI\alpha=\dfrac{\tau}{I}

Where τ\tau is the torque, and II is the moment of inertia. For the cylinder, the previous equation will be:

α1=2τmR2(1)\begin{aligned} \alpha_1&=\dfrac{2 \tau}{mR^2} \tag{1} \end{aligned}

Rearrange the last equation. For the situation when R=4RR=4R, which is the case in our problem:

α2=2τm(4R)2α2=2τ16mR2\begin{aligned} \alpha_2&=\dfrac{2 \tau}{m (4R)^2}\\ \alpha_2&=\dfrac{2 \tau}{16mR^2} \end{aligned}

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