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Why does white phosphorus consist of tetrahedral P4\mathrm{P}_4 molecules while nitrogen consists of diatomic N2\mathrm{N}_2 molecules?

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Answered 2 years ago
Answered 2 years ago

Nitrogen exists as a diatomic molecule N2\text{N}_{2} because it forms three bonds (1 σ\sigma bond and two π\pi bonds) with another nitrogen, making the N2\text{N}_{2} molecule very stable. Meanwhile, phosphorus exists as P4\text{P}_{4} since it doesn't form strong π\pi bonds with another phosphorus. This can be attributed to the atomic size of phosphorus. Since phosphorus has a bigger atomic size than nitrogen, the overlap of the π\pi orbitals are smaller, and thus the resulting π\pi bonds are weaker. Therefore, phosphorus needs to form three σ\sigma bonds with other phosphorus, forming the P4\text{P}_{4} molecule. With this, the molecular geometry of P4\text{P}_{4} is tetrahedral, while the molecular geometry of N2\text{N}_{2} is linear.

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