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Why is the following situation impossible? A book sits on an inclined plane on the surface of the Earth. The angle of the plane with the horizontal is 60.060.0^{\circ}. The coefficient of kinetic friction between the book and the plane is 0.300. At time t = 0, the book is released from rest. The book then slides through a distance of 1.00 m, measured along the plane, in a time interval of 0.483 s.

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We know that the angle of inclination is θ=60.0°\theta=60.0\text{\textdegree}, the coefficient of kinetic friction between book surface, the inclination surface is μ=0.300\mu=0.300 and the acceleration due to gravity is g=9.81 m/s2g=9.81\ {\rm m/s^{2}}. The book was released with initial velocity u=0u=0 at time t=0t=0 and traveled a distance d=1.00 md=1.00\ {\rm m}. We have to calculate the the time taken to travel the distance. If the calculated time does not matches with the given time interval t=0.483 st=0.483\ {\rm s} then the given situation is impossible.

Consider the mass of the book is mm, hence, the weight of the book is w=mgw=mg. The weight of the book act vertically downwards. Now the component of the weight parallel to the surface of inclination is w=wsinθ=mgsinθw_{\parallel}=w\sin\theta=mg\sin\theta.

Now, the component of the weight perpendicular to the surface of inclination is w=wcosθ=mgcosθw_{\perp}=w\cos\theta=mg\cos\theta. Hence, the normal reaction of the surface on the book is N=mgcosθN=mg\cos\theta. Hence, the friction force is Ff=μN=μmgcosθF_{f}=\mu N=\mu mg\cos\theta.

Hence, the total force acting on the books is

F=wFf=mgsinθμmgcosθ\begin{align*} F & =w_{\parallel}-F_{f}\\ & =mg\sin\theta-\mu mg\cos\theta \end{align*}

Hence, the acceleration of the book is

a=Fm=mgsinθμmgcosθm=gsinθμgcosθ\begin{align*} a & =\frac{F}{m}\\ & =\frac{mg\sin\theta-\mu mg\cos\theta}{m}\\ & =g\sin\theta-\mu g\cos\theta \end{align*}

Now substituting the values we have

a=(9.81 m/s2)sin(60.0°)(0.300)(9.81 m/s2)cos(60.0°)=7.02 m/s2\begin{align*} a & =\left(9.81\ {\rm m/s^{2}}\right)\sin\left(60.0\text{\textdegree}\right)-\left(0.300\right)\left(9.81\ {\rm m/s^{2}}\right)\cos\left(60.0\text{\textdegree}\right)\\ & =7.02\ {\rm m/s^{2}} \end{align*}

Hence, time taken by the book to travel the distance d=1.00 md=1.00\ {\rm m} is

t=2da=2(1.00 m)(7.02 m/s2)=0.534 s\begin{align*} t & =\sqrt{\frac{2d}{a}}\\ & =\sqrt{\frac{2\left(1.00\ {\rm m}\right)}{\left(7.02\ {\rm m/s^{2}}\right)}}\\ & =0.534\ {\rm s} \end{align*}

Hence, the book can not reach the distance in 0.483 second, hence, the given situation is impossible.

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