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Question

Write an equation for the circle that satisfies the set of conditions.

center at (4,2)(4,2), tangent to xx-axis

Solution

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Answered 2 years ago
Answered 2 years ago
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Given the center (4,2)(4,2) and knowing that the circle is tangent to xx-axis, we can conclude that the radius is 22.

Write in standard form using the center (4,2)(4,2) and r=2r=2.

(xh)2+(yk)2=r2(x4)2+(y2)2=(2)2substitute & simplify(x4)2+(y2)2=4\begin{aligned} (x-h)^2+(y-k)^2&=r^2\\ (x-4)^2+(y-2)^2&=(2)^2&&\text{substitute \& simplify}\\ (x-4)^2+(y-2)^2&=4 \end{aligned}

Therefore the equation is (x4)2+(y2)2=4(x-4)^2+(y-2)^2=4

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