Try the fastest way to create flashcards
Question

# Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the graph of the given line.$(-1,2), y=\frac{1}{2} x-3$

Solution

Verified
Step 1
1 of 3

\begin{align*} y&=mx+b\\ 2&=\dfrac{1}{2}(-1)+b\\ 2&=-\dfrac{1}{2}+b\\ \dfrac{5}{2}&=b \end{align*}

Parallel lines have the same slope. Since $y=\dfrac{1}{2}x-3$ has a slope of $\dfrac{1}{2}$, then the slope of the line you must write has a slope of $m=\dfrac{1}{2}$. Substitute this slope and the point $(-1,2)$ into slope-intercept form of a line and solve for $b$.

## Recommended textbook solutions

#### Glencoe Algebra 1

1st EditionISBN: 9780079039897McGraw-Hill Education
6,685 solutions

#### enVision Algebra 1

1st EditionISBN: 9780328931576Al Cuoco, Christine D. Thomas, Danielle Kennedy, Eric Milou, Rose Mary Zbiek
3,653 solutions

#### Algebra 1

4th EditionISBN: 9781602773011Saxon
5,377 solutions

#### Big Ideas Math Integrated Mathematics II

1st EditionISBN: 9781680330687Boswell, Larson
4,539 solutions