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Question

Write the equation in standard form. State whether the graph of the equation is a parabola, circle, ellipse, or hyperbola. Then graph the equation.

9y2+18y=25x2+2169 y^2+18 y=25 x^2+216

Solution

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Answered 2 years ago
Answered 2 years ago
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Rewrite the given into standard form.

9y2+18y=25x2+216\begin{aligned} 9y^2+18y=25x^2+216 \end{aligned}

Arrange and use APE

[9y2+18y]25x2=216\begin{aligned} \left[9y^2+18y\right]-25x^2=216 \end{aligned}

Factor out 99

9[y2+2y]25x2=216\begin{aligned} 9\left[y^2+2y\right]-25x^2=216 \end{aligned}

Complete the square

9[y2+2y+(b2)2]25x2=216+9(b2)2\begin{aligned} 9\left[y^2+2y+\left(\frac{b}{2}\right)^2\right]-25x^2=216+9\left(\frac{b}{2}\right)^2 \end{aligned}

Substitute

9[y2+2y+(22)2]25x2=216+9(22)2\begin{aligned} 9\left[y^2+2y+\left(\frac{2}{2}\right)^2\right]-25x^2=216+9\left(\frac{2}{2}\right)^2 \end{aligned}

Simplify

9[y2+2y+(1)2]25x2=216+9(1)29(y2+2y+1)25x2=225\begin{aligned} 9\left[y^2+2y+(1)^2\right]-25x^2&=216+9(1)^2\\ 9(y^2+2y+1)-25x^2&=225 \end{aligned}

Factor

9(y+1)225x2=225\begin{aligned} 9(y+1)^2-25x^2=225 \end{aligned}

Equate to 11

9(y+1)222525x2225=225225(y+1)225x29=1\begin{aligned} \frac{9(y+1)^2}{225}-\frac{25x^2}{225}&=\frac{225}{225}\\ \frac{(y+1)^2}{25}-\frac{x^2}{9}&=1 \end{aligned}

Hence, the standard form is (y+1)225x29=1\dfrac{(y+1)^2}{25}-\dfrac{x^2}{9}=1 and indicates that the graph is Hyperbola.

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