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Question

You and your tean1 are designing a device that can be used to position a small, plastic object in the region between the plates of a parallel-plate capacitor. A small plastic sphere of mass m=1.20×102m=1.20 \times 10^{-2} kg carries a charge q=+0.200μCq=+0.200 \mu \mathrm{C} and hands vertically (along the y direction) from a massless, insulating thread (length l=10.0 cm) between two vertical capacitor plates. When there is no electric field, the object resides at the midpoint between the plates (at x=0). However, when there is a field between plates (in the ±x\pm x direction) the object moves to a new equilibrium position.

To what value should you set the field if you want the object to be located at x=2.10 cm?

Solution

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Answered 5 months ago
Answered 5 months ago
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a) To be able to find electric field strength between plates of capacitor, we have to first write Newton's equation for forces that holds positive charged ball in given position. Lets first draw graph.

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