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Your company, Sonic Video, Inc., has conducted research that shows the following probability distribution, where X is the number of video arcades in a randomly chosen city with more than 500,000 inhabitants.

x0123456789P(X=x).07.09.35.25.15.03.02.02.01.01\begin{matrix} \text{x} & \text{0} & \text{1} & \text{2} & \text{3} & \text{4} & \text{5} & \text{6} & \text{7} & \text{8} & \text{9}\\ \text{P(X=x)} & \text{.07} & \text{.09} & \text{.35} & \text{.25} & \text{.15} & \text{.03} & \text{.02} & \text{.02} & \text{.01} & \text{.01}\\ \end{matrix}

a. Compute μ=E(X)\mu=E(X) and interpret the result. b. Which is larger, P(X<μ)P(X<\mu) or P(X>μ)P(X>\mu)? Interpret the result.

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Answered 2 years ago
Answered 2 years ago
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Given a relative frequency table for a random variable, we need to

a.     compute the population mean,     μ=E(X)\mu=E(X), and

b.     compare P(X<μ)P(X<\mu)and P(X>μ)P(X>\mu). Also, interpret the comparison

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