## Related questions with answers

Zorch, an archenemy of Rotation Man, decides to slow Earth's rotation to once per 28.0 h by exerting an opposing force at and parallel to the equator. Rotation Man is not immediately concerned, because he knows Zorch can only exert a force of

$4.00 × 10^7 N$

(a little greater than a Saturn V rocket's thrust). How long must Zorch push with this force to accomplish his goal? (This period gives Rotation Man time to devote to other villains.)

Solution

VerifiedFirst, we calculate the torque $\left(\tau\right)$ produced by the force $\left(F\right)$. We also need to calculate the moment of inertia of Earth about its axis $\left(I_\text{Earth}\right)$.

$\begin{align*} \tau&=- R_\text{Earth} F \\ &=- \left(6.37 \cdot 10^6\right) \left(4.00 \cdot 10^7\right) \\ &=-2.55 \cdot 10^{14} \text{ N}\cdot \text{m} \\ I_\text{Earth}&=\dfrac{2}{5} M_\text{Earth} {R_\text{Earth}}^2 \\ &=\dfrac{2}{5} \left(5.95 \cdot 10^{24}\right) \left(6.37 \cdot 10^6\right)^2 \\ &=9.66 \cdot 10^{37} \text{ kg}\cdot \text{m}^2 \end{align*}$

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