$$x^{2}\cdot y-x^{2}+4\cdot y=0$$

Find any intercept :

Y-intercept :

let $x=0$ ans solve for $y$:

$$\begin{align*} 0&=x^{2}\cdot y-x^{2}+4\cdot y\\ x^{2}&=x^{2}\cdot y+4\cdot y\\ x^{2}&=y\cdot \left(x^{2}+4 \right)\\ y&=\dfrac{x^{2}}{x^{2}+4}\\ y&=\dfrac{0^{2}}{0^{2}+4}\\ y&=0\\ \end{align*}$$

y-intercept is $\left(0,0 \right)$

X-intercept :

Let $y=0$ and solve $x$:

$$\begin{align*} y&=\dfrac{x^{2}}{x^{2}+4}\\ 0&=\dfrac{x^{2}}{x^{2}+4}\\ 0&=x^{2}\\ x&=0\\ \end{align*}$$

x-intercept is $\left(0,0 \right)$