Exercise b

Chapter 8, Section 8-1, Page 345
enVision Geometry 1st Edition by Al Cuoco
ISBN: 9780328931583

Solution

Verified

From part (a), we already found that:

AD=5\color{#c34632}{AD=5}

Since AC=BC=52AC=BC=5\sqrt{2}, we can use Pythagorean Theorem to find ABAB:

AB2=AC2+BC2AB^2=AC^2+BC^2

AB2=(52)2+(52)2AB^2=(5\sqrt{2})^2+(5\sqrt{2})^2

AB2=50+50AB^2=50+50

AB2=100AB^2=100

AB=10\color{#c34632}{AB=10}

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