Exercise c

Chapter 8, Section 8-1, Page 345
enVision Geometry 1st Edition by Al Cuoco
ISBN: 9780328931583

Solution

Verified

The length of the hypotenuse of ABC\triangle ABC is 1010 and the length of its sides is 525\sqrt{2} so if we divide them, we get:

1052=22=2\dfrac{10}{5\sqrt{2}}=\dfrac{2}{\sqrt{2}}=\color{#c34632}{\sqrt{2}}

The length of the hypotenuse of ADC\triangle ADC is 525\sqrt{2} and the length of its sides is 55 so if we divide them, we get:

525=2\dfrac{5\sqrt{2}}{5}=\color{#c34632}{\sqrt{2}}

The ratio of the hypotenuse and one of the congruent legs in a 45°45\text{\textdegree}-45°45\text{\textdegree}-90°90\text{\textdegree} triangle is 2\sqrt{2}.

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